[Answered] How Debug A Application Python Wsgi In Tommy

[cgarcia]

Hello.

someone knows, how to debug an application flask in python this is my code

 

/home/cgarciar/public_html/flask/myapp.py

 

#! /usr/bin/python3.6

import sys
from flask import Flask
#, __version__
app = Flask(__name__)
application = app

@app.route("/")
def hello():
return "Hello world!"

@app.route("/flask/version/")
def p_version():
return "Flask version %s" % __version__

if __name__ == "__main__":
app.run()

 

 

and file : /home/cgarciar/public_html/flask/flask.wsgi

 

#! /usr/bin/python3.6

import sys
import os

sys.path.append('/home/cgarciar/public_html/flask')

os.path.insert(0,os.path.dirname(__file__))
from myapp import app as application

# make the secret code a little better
application.secret_key = 'secret'

 

 

with permission 755

 

y result see "http://www.cesly.heliohost.org/flask/flask"

 

 

 

[Krydos]

os.path.insert(0,os.path.dirname(__file__))

And the wiki says

sys.path.insert(0, os.path.dirname(__file__))

Source: http://wiki.helionet.org/Flask

[cgarcia]

Thanks, it worked ok.
It was very simple.