Genre Php Function

[Oliver Briggs]

$servergenre = explode('<SERVERGENRE>',$content);

$servergenre = explode('</SERVERGENRE>',$servergenre[1]);

hi there have i done the php code right for it to show on the radio panel

[wolstech]

I assume you want the value between the <servergenre> and </servergenre> tags. Explode breaks a string up into an array using the first argument as the delimiter, and is not the right function for this (though with some creativity and the trim() function, it could probably be made to work)

 

Seeing that the format of the source data is likely XML, look up PHP SimpleXML. It makes it much easier to get any value you could possibly want with very little effort. This is the example page: http://php.net/manual/en/simplexml.examples-basic.php

[Oliver Briggs]

oh i see ok and can you code it for me on both line number 106

107

in notepad++ the genre php function and thanks

new.php

[wolstech]

Unfortunately I cannot write your code for you (both because I don't know the environment and data being passed to this program, and because we generally do not provide coding assistance except for troubleshooting compatibility with our servers).

 

If you have trouble developing it though, feel free to ask questions. This site on PHP's website should get you started on how to handle your data, assuming your data is XML: http://php.net/manual/en/book.simplexml.php

[Byron]

Here's another good forum for coding help: http://www.codingforums.com/