MDkate
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Posts posted by MDkate
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Without the backticks, PHP is assuming $id is a variable. The variable is empty and this creates a syntax error.
You don't get any error when trying the other way?
Edit: Try using mysql_query with apostrophes so the variable will not be parsed. I think PHP will still assume it's a variable.
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Good morning. I would like to request second account access for Johnny in the hopes of further progressing my programming knowledge into the fields of ASP.NET and ROR (eventually Java, but I see the queue is backed up past april :)/>).
My current information is:
Username:
Domain:
Server: Stevie
Thank you for any support in this matter.
[Answered] How To Run Java Applications
in Questions
Posted
As stated in the features upon signup, each user gets one .war deploy.