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Hi, Is create user syntax allowed when i execute that statement? I wanted to allow a user to be registered on MySQL (not thru cpanel) so that the max_user connection will not show in the future.

Hello. I recently got a For Dummies book on C++ and really want to get started, but I can't find a good place to download C++ or Code::Blocks. Anyone know where I should go for the downloads and what I should do when I get there? int main() { cout << "Thanks for your help!" << end1; return 0; }

Hello, Everyone. I'm having problems with my CGI executable on my site. It gives HTTP 500 Internal Server Error while I have no access to any detailed logs to be able to troubleshoot the problem. It works well on my computer. The permissions of the file are set correctly (755). And another "Hello, World!" CGI program works perfectly on the server. It seems to me that this is a linking issue. Here are the details of the executable: The executable is linked with the following libraries: Source Code: #include <iostream> #include <mysql.h> using namespace std; const string CRLF = "\r\n"; int main() { cout << "Content-Type: text/plain" << CRLF << CRLF; cout << "Hello, World!" << CRLF; try { cout << "MySQL Client Version: " << mysql_get_client_info() << CRLF; } catch(exception& ex) { cout << "ERROR: " << ex.what() << CRLF; } return 0; } Compiled Using: gcc 4.7 with the following specifications: Makefile: #Variables: INCLUDE_DIR = -I/usr/local/mysql/include LIBS_DIR = -L/usr/local/lib64 STATIC_LIBS = -lmysqlclient DYNAMIC_LIBS = -ldl -lpthread -lrt STATIC_LINK_FLAG = -Wl,-Bstatic DYNAMIC_LINK_FLAG = -Wl,-Bdynamic LD_FLAGS = $(LIBS_DIR) $(STATIC_LINK_FLAG) $(STATIC_LIBS) $(DYNAMIC_LINK_FLAG) $(DYNAMIC_LIBS) #Rules: test.cgi: test.cpp g++ test.cpp $(INCLUDE_DIR) $(LD_FLAGS) -o test.cgi