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Hi. I am working on a quadratic formula solver, just for fun. Here is the code I need fixed:

var $a, $b, $c, $d, $e, $f, $g, $h, $$A, $$B, a, b, c;
function solve(x, y, z) {
 a = document.getElementById("A_").value;
 b = document.getElementById("B_").value;
 c = document.getElementById("C_").value;
$a = (-1 * B)/>;
$b = (2 * a);
$c = Math.pow(b, 2);
$d = (4 * a * c);
$e = ($c - $d);
if ($e >= 0) {
 $f = Math.sqrt($e);
 $g = ($a + $f);
 $h = ($a - $f);
 $$A = ($g / $B)/>;
 $$B = ($h / $B)/>;
if ($$A == $$B)/> {
	return $$A;
} else if (Math.abs($$B)/> == $$A) {
	return "± " + $$A;
} else {
return $$A + " or " + $$B;
} else {
return "I'm sorry, this calculator can not compute imaginary solutions.";
}

Apparently, I am misusing the brackets, parentheses, etc. I have a version that works:

function solve(x, y, z) {
 a = document.getElementById("A_").value;
 b = document.getElementById("B_").value;
 c = document.getElementById("C_").value;
$a = (-1 * B)/>;
$b = (2 * a);
$c = Math.pow(b, 2);
$d = (4 * a * c);
$e = ($c - $d);
if ($e >= 0) {
 $f = Math.sqrt($e);
 $g = ($a + $f);
 $h = ($a - $f);
 $$A = ($g / $B)/>;
 $$B = ($h / $B)/>;
if ($$A == $$B)/> {						  
	return $$A;
} else {
	return $$A + " or " + $$B;			
}
} else {
return "I'm sorry, this calculator can not compute imaginary solutions.";
}
}

But I want to insert the "else if" statement, which I seem to be doing wrong.

Anyone know the (probably embarassingly obvious) solution? If so, can you please show me what to do?

Thanks!

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