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centellajs

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    Flask App Implementing Trouble .htaccess

    in Website Management and Coding

    Posted

    Really Thx in advanced .

     

    Hi i am just new in the python world , i need to execute a flaskapp for whatsapp sending messages, i followed the steps to implement the flaskapp but i can't execute any code for python native or flask worst it produces an error i followed all the steps to implement flask

     

     

    I really need to make it works the .htaccess looks like

     

    /home/xtremese/public_html/inteygratemyfrank-i/.htaccess
    RewriteEngine On
    RewriteBase /
    RewriteRule ^(media/.*)$ - [L]
    RewriteRule ^(admin_media/.*)$ - [L]
    RewriteRule ^(inteygratemyfrank-i\.wsgi/.*)$ - [L]
    RewriteRule ^(.*)$ inteygratemyfrank-i/flask.wsgi/$1 [QSA,PT,L]

     

     

    my flask.wsgi looks like

     

    import os, sys
    # edit your username below
    sys.path.append("/home/xtremese/public_html/inteygratemyfrank-i");
    sys.path.insert(0, os.path.dirname(__file__))
    from myapp import app as application
    # make the secret code a little better
    application.secret_key = 'secret'
    Create a python script named myapp.py
    import sys
    from flask import Flask, __version__
    app = Flask(__name__)
    application = app
    @app.route("/")
    def hello():
    return """
    HelioHost rules!<br><br>
    <a href="/flask/python/version/">Python version</a><br>
    <a href="/flask/flask/version/">Flask version</a>
    """
    @app.route("/python/version/")
    def p_version():
    return "Python version %s" % sys.version
    @app.route("/flask/version/")
    def f_version():
    return "Flask version %s" % __version__
    if __name__ == "__main__":
    app.run()

     

    and my files structure looks like :

     

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